Heron's formula for finding area of the triangle is given by
Area=sqrt(s(s-a)(s-b)(s-c))Area=√s(s−a)(s−b)(s−c)
Where ss is the semi perimeter and is defined as
s=(a+b+c)/2s=a+b+c2
and a, b, ca,b,c are the lengths of the three sides of the triangle.
Here let a=14, b=9a=14,b=9 and c=15c=15
implies s=(14+9+15)/2=38/2=19⇒s=14+9+152=382=19
implies s=19⇒s=19
implies s-a=19-14=5, s-b=19-9=10 and s-c=19-15=4⇒s−a=19−14=5,s−b=19−9=10ands−c=19−15=4
implies s-a=5, s-b=10 and s-c=4⇒s−a=5,s−b=10ands−c=4
implies Area=sqrt(19*5*10*4)=sqrt3800=61.644⇒Area=√19⋅5⋅10⋅4=√3800=61.644 square units
implies Area=61.644⇒Area=61.644 square units
