How do you use Heron's formula to find the area of a triangle with sides of lengths #18 #, #7 #, and #13 #?

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Answer 1 · 2016-01-26T05:18:54

#6sqrt38.sq.cm^2#

Use Heron's formula:-
#sqrt[s(s-a)(s-b)(s-c)]#
Where #s#=semi-perimeter of triangle=#(a+b+c)/2#

So,#a=18,b=7,c=13,s=19=(18+7+13)/2=38/2#

#rarrsqrt[s(s-a)(s-b)(s-c)]#

#rarrsqrt[19(19-18)(19-7)(19-13)]#

#rarrsqrt[19(1)(12)(6)]#

#rarrsqrt[19(72)]#

#rarrsqrt[1368]=6sqrt38#