How do you use Hess's Law to calculate enthalpy for this reaction?
Given Data:
"N"_2(g) + "O"_2(g) -> 2"NO"(g)
DeltaH = +"180.7 kJ"
2"NO"(g) + "O"_2(g) -> 2"NO"_2(g)
DeltaH = -"113.1 kJ"
2"N"_2"O"(g) -> 2"N"_2(g) + "O"_2(g)
DeltaH = -"163.2 kJ"
Use Hess' Law to calculate DeltaH for the reaction:
"N"_2"O"(g) + "NO"_2(g) -> 3"NO"(g)
Given Data:
DeltaH = +"180.7 kJ"
DeltaH = -"113.1 kJ"
DeltaH = -"163.2 kJ"
Use Hess' Law to calculate
1 Answer
Explanation:
PC of cake
Adding the 3 equations:
Adding one more reaction
Adding previous 2 equations and dividing by 2
Finally,
The Enthalpy is the sum of the all reactions: