Question

How do you use `log_10 7=.8451` to evaluate the expression`log_10 (1 3/7)`?

Answer 1

`0.1549`

Explanation:

`log_10 10 =1`. So, `log_10(1 3/7)=log_10 (10/7)`

`=log_10 10-log_10 7=log_10 10-log_10 7`

`=1-0.8451=0.1549`.