Question

How do you use `log_10 5=.6990 and log_10 7=.8451` to evaluate the expression`log_10 (7/5)`?

Answer 1

0.1461

Explanation:

Use the implied `log` for `log_10 and log (m/n)=log m-log n`.

`log (7/5) = log 7 - log 5=0.8451-0.6990=0.1461`.