How do you use properties of Logarithms to rewrite the following as the logarithm of a single number (no decimal values) #2 log 7 + log 3#?

1 Answer
Jul 6, 2015

Answer:

#2log7 + log3 = log147#

Explanation:

First Property: #log(x^d) = dlogx# or #dlogx = log(x^d)#

So

#2log7 + log3 = log(7^2) +log3#

#2log7 + log3 = log49 +log3#

Second Property: #log(xy) = logx +logy# or #logx +logy = log(xy) #

So

#2log 7+ log3 = log 49 + log 3 = log(49×3)#

#2log 7+ log3 = log147#