# How do you use sigma notation to write the sum for #1/(3(1))+1/(3(2))+1/(3(3))+...+1/(3(9))#?

##### 2 Answers

#### Answer:

# sum_(i=1)^9 1/(3i) #

#### Explanation:

The first term is:

# u_1 = 1/(3*1) #

The second term is:

# u_2 = 1/(3*2) #

The third term is:

# u_2 = 1/(3*3) #

#vdots#

The

# u_i = 1/(3*i) #

There are nine terms; so the sum is:

# sum_(i=1)^9 1/(3i) #

#### Answer:

#### Explanation:

Sigma notation is used in mathematics to condense a sum of terms into a more readable format. Each term will vary according to an integer, **i**, which is incremented by 1. (i.e.

In sigma notation, the term below the

In this example,

Looking at the original question,

**Note:** Since