Question

How do you use sigma notation to write the sum for `[2(1/8)+3)]+[2(2/8)+3]+...+[2(8/8)+3]`?

Answer 1

`= sum_(k = 1)^8 k/4 + 3`

Explanation:

First just transcribe it verbatim:

`= sum_(k = 1)^8 2 (k/8) + 3`

Then you can simplify a bit:

`= sum_(k = 1)^8 k/4 + 3`