How do you use sigma notation to write the sum for [2(1/8)+3)]+[2(2/8)+3]+...+[2(8/8)+3]?

Mar 4, 2017

$= {\sum}_{k = 1}^{8} \frac{k}{4} + 3$

Explanation:

First just transcribe it verbatim:

$= {\sum}_{k = 1}^{8} 2 \left(\frac{k}{8}\right) + 3$

Then you can simplify a bit:

$= {\sum}_{k = 1}^{8} \frac{k}{4} + 3$