How do you use substitution to solve the system of equations #2x+y=-7# and #-5x+2y = 22#?

1 Answer
Aug 1, 2016

#x = -4, y =1#

Explanation:

The clue that substitution would be a good method, is the
single #y# term in the first equation.

#2x +color(red) y = -7" "rArr color(red)(y = -2x-7)#

In the other equations, replace #color(red)(y)# by #color(red)((-2x-7))#

#-5x +2color(red)y = 22#

#-5x +2color(red)((-2x-7)) = 22#

#-5x -4x-14 = 22#

#-9x = 22+14#

#-9x = 36" "color(blue)(x = -4)#

Now that we know the value for #x#, sub it to find y.

#y = -2color(blue)((-4))-7#

#y = +8-7 = 1" "color(red)(y=1)#