How do you use synthetic substitution to evaluate f(-2) for #f(x)=x^3-3x^2-x-9#? Precalculus Real Zeros of Polynomials Synthetic Division 1 Answer Alan P. Nov 13, 2015 #f(-2)= -27# Explanation: #f(x)=color(blue)(1)x^3color(blue)(-3)x^2color(blue)(-1)xcolor(blue)(-9)# at #f(color(cyan)(-2))# #{: (,,color(blue)(1),color(blue)(-3),color(blue)(-1),color(blue)(-9)), (,,,-2,10,-18), (,,"----","----","----","----"), (xx(color(cyan)(-2)),"|",1,-5,9,color(red)(-27)) :}# Answer link Related questions What is synthetic division? What are common mistakes students make with synthetic division? How do I find the quotient and remainder using synthetic division? How do you write the remainder in synthetic division? How do I find the quotient #(x^3+5x^2+x-15)/(x+3)# by using synthetic division? How do I find the roots of a polynomial function by using synthetic division? How can synthetic division be used to factor a polynomial? How do I use synthetic division to find #p(-3)# for #p(x)=x^4-2x^3-4x+4#? Use synthetic division to find #p(4)# for #p(x)=x^4-2x^3-4x+4#? How do you use synthetic division to evaluate #f(3)# given that #f(x)=x^3+2x^2-7x+8#? See all questions in Synthetic Division Impact of this question 2108 views around the world You can reuse this answer Creative Commons License