How do you use the binomial #(3-2z)^4# using Pascal's triangle?

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Answer 1 · 2018-01-29T02:31:12

#color(green)((3-2z)^4 = 243 - 216 z + 216 z^2 - 96 z^3 + 16z^4)#

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As seen from the Pascal's triangle,

1 4 6 4 1

#(3-2z)^4 = 1 * 3^4* (2z)^0 - 4 * 3^3 (2z) + 6 * 3^2 (2z)^2 - 4 * 3 * (2z)^3 + 1 * 3^0 * (2z)^4#

#color(green)((3-2z)^4 = 243 - 216 z + 216 z^2 - 96 z^3 + 16z^4)#