How do you use the binomial series to expand #(x – 2)^5#?

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Answer 1 · 2016-02-01T09:07:20

Us the pascal's triangle to find the answer easily:

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#rarr(a+b)^5=1a^5+5a^4b+10a^3b^2+10a^2b^3+5ab^4+1b^5#

#rarr(x-2)^5#

#=1(x^5)+5(x^4)(-2)+10(x^3)(-2^2)+10(x^2)(-2^3)+5x(-2^4)+(-2^5)#

#=x^5+5x^4(-2)+10x^3(-2^2)+10x^2(-2^3)+5x(-2^4)+(-2^5)#

#=x^5+5x^4(-2)+10x^3(4)+10x^2(-8)+5x(16)+(-32)#

#=x^5-10x^4+40x^3-80x^2+80x-32#