How do you use the Binomial Theorem to expand #(1/3x – 9) ^20#?

1 Answer
Feb 9, 2018

Answer:

It will be almost impossible to provide the entire answer, but I will tell you how to do so.

Explanation:

The binomial theorem states that:

#(x+a)^n=sum_(k=0)^n((n),(k))x^(n-k)a^k#, where #((n),(k))=(n!)/(k!(n-k)!)#.

Here, #x=1/3x,a=-9,n=20#.

So the above equation becomes:

#(1/3x-9)^20=sum_(k=0)^20((20),(k))(1/3x)^(20-k)(-9)^k#

If you were to solve the above, you would get your answer.