# How do you use the Binomial Theorem to expand (3v+s)^5?

Now we have that $x = 3 v$ and $y = s$ applying the binomial theorem
${\left(3 v + s\right)}^{5} = {s}^{5} + 15 {s}^{4} v + 90 {s}^{3} {v}^{2} + 270 {s}^{2} {v}^{3} + 405 s {v}^{4} + 243 {v}^{5}$