How do you use the double angle or half angle formulas to simplify #cos^2 4x - sin^2 4x#?

1 Answer
Oct 31, 2015

#cos(8x)#.

Explanation:

We know that #cos(2y)=cos^2(y)-sin^2(y)#. So, in your case, the role of #y# is being played by #4x#.

Trying to convert the formula in words, you can write #cos^2(y)-sin^2(y)=cos(2y)# as

"the difference between the squares of the cosine and the sine of an angle is the cosine of twice that angle".

And what do you have? #cos^2(4x)-sin^2(4x)# is exactly the difference between the squares of the cosine and the sine of an angle, namely of #4x#. This means that #cos^2(4x)-sin^2(4x)# is the cosine of twice the angle, namely #2*4x=8x#.