How do you use the factor theorem to determine whether x-5 is a factor of #3x^2 + 7x + 40#?

1 Answer
Jan 10, 2016

Substitute #x=5# and see if the result is #0#.

Explanation:

If #f(x) = 3x^2+7x+40# then #(x-5)# is a factor if and only if #f(5) = 0#

We find:

#f(5) = 3*5^2+7*5+40 = 75+35+40 = 150 != 0#

So #(x-5)# is not a factor.

In fact we can tell that #3x^2+7x+40# has no factors with Real coefficients, since its discriminant is negative:

#Delta = b^2-4ac = 7^2-(4*3*40) = 49-480 = -431#