How do you use the fundamental identities to simplify #cot(pi/2-x)cosx#?
1 Answer
Jan 27, 2017
Explanation:
Using the
#color(blue)"trigonometric identities"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(cot(pi/2-x)=tanx;tanx=(sinx)/(cosx))color(white)(2/2)|)))#
#rArrcot(pi/2-x)cosx#
#=tanxcosx#
#=(sinx)/cancel(cosx)xxcancel(cosx)=sinx#
