# How do you use the intermediate value theorem to explain why #f(x)=1/16x^4-x^3+3# has a zero in the interval [1,2]?

##### 1 Answer

Nov 3, 2016

The function is continuous and

#### Explanation:

The function

Therefore we calculate

and

Therefore as

As one value is above zero and the other below zero

graph{x^4/16-x^3+3 [-5.94, 6.55, -3.34, 2.9]}