Question

How do you use the moment generating function of a chi-squared distribution to find the standard deviation?

Answer 1

If M(t) is differentiable at zero, then the nth moments about the origin are given by `M^((n))(0)`

Explanation:

mean `=M'(0)`

variance `=M''(0)-[M'(0)]^2`

s.d. `=sqrt(variance)`

hope that helped