How do you use the properties of logarithms to expand #ln (6/sqrt(x^2+1))#?

1 Answer
May 25, 2017

Answer:

#ln6-1/2ln(x^2+1)#

Explanation:

Expand #ln(6/(sqrt(x^2+1)))#

Rewrite the square root as an exponent.

#ln(6/(x^2+1)^(1/2))#

Use the log property #log(a/b)=loga - logb#

#ln6-ln(x^2+1)^(1/2)#

Use the log property #loga^b=bloga#

#ln6-1/2ln(x^2+1)#