How do you use the properties of logarithms to expand #log_4 (5x)#?

1 Answer
Oct 30, 2017

Answer:

#log_4 (5x) =1.16+log_4 x#

Explanation:

#log_4 (5x) = log_4 5 +log_4 x= log5/log4 + log_4 x#

#= 1.16(2dp)+log_4 x#

Properties used are :
#  log_a (xy) = log x + log y and log_a x = log_10 x/log_10 a# 

#log_4 (5x) =1.16+log_4 x# [Ans]