How do you use the quotient rule to find the derivative of #y=tan(x)# ? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Ratnaker Mehta Mar 6, 2018 Kindly refer to the Explanation. Explanation: #"The Quotient Rule for Differentiation : "(u/v)'=(vu'-uv')/v^2#. #:. d/dx(tanx)=(sinx/cosx)'#, #={cosx*(sinx)'-sinx*(cosx)'}/(csx)^2#, #={cosx*cosx-sinx(-sinx)}/cos^2x#, #={cos^2x+sin^2x}/cos^2x#, #=1/cos^2x#. # rArr (tanx)'=sec^2x#. Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? How do you use the quotient rule to find the derivative of #y=(1-x*e^x)/(x+e^x)# ? See all questions in Quotient Rule Impact of this question 15253 views around the world You can reuse this answer Creative Commons License