# How do you use the rational root theorem to find the roots of #10x^4 + x^3 + 7x^2 + x -3 = 0#?

##### 1 Answer

#### Answer:

See explanation...

#### Explanation:

By the rational root theorem, any rational roots of

So the possible rational roots are:

#+-1/10# ,#+-1/5# ,#+-3/10# ,#+-1/2# ,#+-3/5# ,#+-1# ,#+-3/2# ,#+-3#

Let's try to narrow down the search a little.

#f(0) = -3#

#f(1) = 10+1+7+1-3 = 16#

So there is a Real root in the interval

Let us calculate

#f(3/10) = 10(3/10)^4+(3/10)^3+7(3/10)^2+(3/10)-3#

#=81/1000+27/1000+63/100+3/10-3#

#=(81+27+630+300-3000)/1000#

#=-1962/1000 < 0#

So the remaining possible positive rational roots are

#f(1/2) = 10(1/2)^4+(1/2)^3+7(1/2)^2+1/2-3#

#=5/8+1/8+7/4+1/2-3#

#=(5+1+14+4-24)/8 = 0#

So

If we separate out this factor, it's easy to spot the the remaining cubic factor will factor easily by grouping:

#10x^4+x^3+7x^2+x-3 = (2x-1)(5x^3+3x^2+5x+3)#

#=(2x-1)((5x^3+3x^2)+(5x+3))#

#=(2x-1)(x^2(5x+3)+(5x+3))#

#=(2x-1)(x^2+1)(5x+3)#

So the remaining rational root is