# How do you use the rational root theorem to find the roots of 2x^3 - 9x^2 - 11x +8 = 0?

If $\frac{p}{q}$ is a root of $2 {x}^{3} - 9 {x}^{2} - 11 x + 8 = 0$ expressed in lowest terms, then $p$ is a divisor of the constant term $8$ and $q$ is a divisor of the coefficient $2$ of the highest order term.
$- 8$, $- 4$, $- 2$, $- 1$, $- \frac{1}{2}$, $\frac{1}{2}$, $1$, $2$, $4$ or $8$.