# How do you use the rational root theorem to find the roots of x^3 + 2x^2 + 3x + 6 = 0 ?

-2, $\pm i \sqrt{3}$
The degree of the polynomial on then left side is odd and the coefficient of its leading term is 1, hence the product of the roots would be -6, these can be $\pm 1 , \pm 2 , \pm 3 , \pm 6$.
From this factorisation, the roots can be writtne as -2, $\pm i \sqrt{3}$