How do you use the rational root theorem to find the roots of #x^3 + 2x^2 + 3x + 6 = 0 #?
The degree of the polynomial on then left side is odd and the coefficient of its leading term is 1, hence the product of the roots would be -6, these can be
Out of these values x= -2 makes the polynomial on the left side 0, hence x+2 would be factor of the polynomial. Now divide the polynomial by x+2,
From this factorisation, the roots can be writtne as -2,