How do you use the remainder theorem to evaluate f(a)=a^3+5a^2+10a+12 at a=-2?

1 Answer
Oct 11, 2017

the remainder of the division (a^3+5a^2+10a+12):(a+2) is 4

Explanation:

We simply will substitute a=-2 in f(a):

f(-2)=(-2)^3+5(-2)^2+10(-2)+12

=-8cancel+20cancel(-20)+12

=4

that means the remainder of the division:

(a^3+5a^2+10a+12):(a+2)

is 4