# How do you use the remainder theorem to find the remainder for each division #(x^2-2)div(x-1)#?

##### 2 Answers

Oct 11, 2017

Quotient

#### Explanation:

```
x 1
………………………………………………………
```

x-1 | x^2 0 2

| x^2 -x

|*_**_*

0 x 2

x -1

*_*

0 3 (Remainder)

Oct 11, 2017

The remainder is

#### Explanation:

The remainder theorem says that:

**For a polynomial #P(x)# the remainder of division #P(x)-:(x-a)# is equal to #P(a)#.**

So instead of using the long division to calculate the remainder only you can substitute

**The remainder of dividision #(x^2-2)-:(x-1)# is #-1#**