How do you use the special product for squaring binomials to multiply $(1/4t+2 )^2$ ?

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Answer 1 · 2014-11-14T20:26:15

By using

$(a+b)^2=a^2+2ab+b^2$ ,

we have

$(1/4t+2)^2=(1/4t)^2+2(1/4t)(2)+(2)^2$

$=1/16 t^2+t+4$

I hope that this was what you meant by "the special product."

How do you use the special product for squaring binomials to multiply (1/4t+2 )^2(1/4t+2 )^2?