# How do you use the Squeeze Theorem to show that limsinx/x as x approaches infinity?

Refer to explanation

#### Explanation:

Hence

$- 1 \le \sin x \le 1 \implies - \frac{1}{x} \le \sin \frac{x}{x} \le \frac{1}{x}$

Hence ${\lim}_{x \to \infty} - \frac{1}{x} = 0$ and ${\lim}_{x \to \infty} \frac{1}{x} = 0$

so ${\lim}_{x \to \infty} \frac{\sin}{x} = 0$