How do you use the trapezoidal rule with n=5 to approximate the area between the curve #y=(3x^2+4x+2)# from 0 to 3?

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Answer 1 · 2015-08-29T16:48:53

#49.296# square units

First, compute the length of your interval #=(3-0)/5=0.6# units

Second, determine the #x#-values you need to use to compute #y# (i.e. #x=0.6, 1.2, 1.8, 2.4, 3.0#)

Third, compute #y# using these #x#-values: #y=5.48,11.12,18.92,28.88,41.00# respectively

Fourth, use the trapezoidal rule:

#A=1/2 (0.6) [5.48 + 2(11.12) + 2(18.92) + 2(28.88) + 41.00]=49.296# square units