How do you use the zero-factor property for the problem x(2x+1)(x-5)=0 ?

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Answer 1 · 2018-04-04T04:37:44

#x = -1/2, 0, 5#

Here's how I did it:

#x(2x+1)(x-5) = 0#

#x = 0#

#2x + 1 = 0#
#2x = -1#
#x = -1/2#

#x-5 = 0#
#x = 5#

#x = -1/2, 0, 5#

Hope this helps!