How do you verify this? sin(x) cos(x) [tan(x) + cot(x)] = 1 Thank you!!

1 Answer
Apr 2, 2018

In the description

Explanation:

Given,
#sinxcosx (tanx+cotx)=1#
From L.H.S
#sinxcosx(tanx+cotx)#
#=sinxcosx. [(sinx)/(cosx) +(cosx)/(sinx)]#
#=sinxcosx [(sinxsinx+cosxcosx)/(sinxcosx)#
#=cancel(sinxcosx)[(sin^2x+cos^2x)/[(cancel(sinxcosx)]#
#=sin^2x+cos^2x#
#=1#
Proved
Thank you.