How do you write $1 - 2 {sin}^{2} 3$ $1-2sin^2 3$ as a single trigonometric function?

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How do you write $1 - 2 {sin}^{2} 3$ $1-2sin^2 3$ as a single trigonometric function?

1 Answer

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Answer 1 · 2016-06-30T03:48:02

${cos 6}^{\circ}$ $cos 6^@$

Explanation:

Apply the trig identity:
$cos 2 a = 1 - 2 {sin}^{2} a,$ $cos 2a = 1 - 2sin^2 a,$
we get:
$cos (6^{\circ}) = 1 - 2 {sin}^{2} (3^{\circ})$ $cos (6^@) = 1 - 2sin^2 (3^@)$

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How do you write $1 - 2 {sin}^{2} 3$ $1-2sin^2 3$ as a single trigonometric function?

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Explanation:

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How do you write $1 - 2 {sin}^{2} 3$ $1-2sin^2 3$ as a single trigonometric function?