How do you write #1.457 times 10 ^2# in standard notation?

1 Answer
Jun 11, 2016

Answer:

#145.7#

Explanation:

Consider #10^2#. This is the same thing as #100#

So by putting together #1.457xx10^2# you are, in effect, stating that you are counting in 100's

So you have 1 at 100's, 4 at 10's and 5 at units. Rounding of with 7 at #10^(ths)#.

So effectively we move the digit of 1 to the left until it occupies the space reserved for hundreds. It will 'drag all the other numbers with it.

We keep the decimal point where it is and move the numbers left 2 times giving

#145.7#