How do you write #(1.68 times 10^-1) / (3 times 10^4)# in standard form?

1 Answer
Oct 19, 2015

Answer:

You can do this in two ways: First the standard forms and then the division, or the other way around. I prefer the second.

Explanation:

Rules of division: divide the numbers, subtract the 10-powers:

#=1.68/3*10^(-1-4)=0.56*10^-5#

Since the 10-power is negative, we move the decimal point 5 to the left:

#=0.0000056#

The other way would be:
#0.168/30000=# (same answer of course)