# How do you write 10^-2=0.01 in Log form?

${\log}_{10} \left(0.01\right) = - 2$
Recall that ${a}^{b} = c \implies {\log}_{a} \left(c\right) = b$
${10}^{-} 2 = 0.01$ $\implies {\log}_{10} \left(0.01\right) = - 2$