# How do you write 11t+2t^2-3+t^5 in standard form and what is the leading coefficients?

##### 1 Answer
Apr 16, 2017

See the solution explanation below:

#### Explanation:

To write this expression in standard form we put the terms in order of the highest exponent to lowest:

$11 t + 2 {t}^{2} - 3 + {t}^{5}$ becomes:

${t}^{5} + 2 {t}^{2} + 11 t - 3$

The leading coefficient for the ${t}^{5}$ term is $1$:

$1 {t}^{5} + 2 {t}^{2} + 11 t - 3$