How do you write 18 as a product of prime factors?

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S.S Share
Jan 8, 2018

Answer:

#2,3 and 3 #

Explanation:

We take 18 and break it down into factors until we reach numbers that are primes.

18 goes to 9 and 2

#18 to 9 and *2* #

9 breaks down further into 3 and 3

#9 to *3* and *3* #

The prime factors are collected at the end and together make the answer.

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4
Jan 18, 2018

Answer:

See explanation.

Explanation:

To write a prime decomposition of a number #x# you follow this procedure:

  1. Find the lowest prime number #p# which divides #x#. Write #x# as a product: #x=p*x_1#
  2. Repeat this procedure until #x_1# is a prime number.
  3. In the final step you can write the product(s) of repeating prime numbers as a power(s).

Here we have:

#x=18#

It is an even number, so we can write that: #18=2*9#

#9# is a compound number; it is divisible by a prime number #3#:

#18=2*3*3#

Now all the numbers are prime, so the decomposition is complete:

#18=2*3*3#

The product of 2 numbers #3# can be written as a power: #3*3=3^2#, so the final answer can be written as:

#18=2*3^2#

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Meave60 Share
Jan 20, 2018

Answer:

#18=2xx3xx3#

Explanation:

Divide #18# by the prime number #2#.

#18-:color(red)2=9#

Divide #9# by the prime number #3#.

#9-:color(red)3=color(red)3#

This is as far as you can go.

#18=color(red)2xxcolor(red)3xxcolor(red)3#

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