# How do you write 2(x-5)^2 + 8 in standard form?

$a {x}^{2} + b x + c = 0$
$2 {\left(x - 5\right)}^{2} + 8$
$= 2 \left({x}^{2} - 10 x + 25\right) + 8$
$= 2 {x}^{2} - 20 x + 58$ is in standard notation