Question

How do you write 3^-2 = 1/9 in log form?

Answer 1

-2=`log_3`(1/9)

Explanation:

A basic log transition is `x=log_b(a)` to `a=b^x`.

If you plug in the variables of `a=1/9`, `b=3`, and `x=-2`, you can go from `a=b^x` (or `3^-2=1/9` if you input the variables) to `x=log_b(a)`, which is equivalent to `-2=log_3(1/9)` if you plug in the variables.