How do you write 3/2 + 5/4 + 9/8 + 17/16 + 33/32 in summation notation?

1 Answer
Apr 17, 2018

#sum_1^n(2^k+1)/2^k#

Explanation:

The denominators are progressing geometrically while the numerators are always 1 greater than their denominators. For the #k^(th)# term in the series the denominator is #2^k#. This makes its numerator #2^k+1#. The sum becomes

#sum_1^n(2^k+1)/2^k#

where #n# is the number of terms in the series.