# How do you write #32=x^5# in Logarithm form?

##### 2 Answers

Aug 28, 2016

Aug 28, 2016

It can be written:

#log_x 32 = 5 " "# or#" " log_32 x = 1/5#

#### Explanation:

Given:

#32 = x^5#

If we take logs base

#log_x 32 = log_x x^5 = 5#

Alternatively, if we take logs base

#1 = log_32 32 = log_32 x^5 = 5 log_32 x#

Hence:

#log_32 x = 1/5#