Question

How do you write `3lna - 6lnb` as a single logarithm?

Answer 1

`3 ln(a) - 6 ln(b) = ln[(a^3)/(b^6)]`

Explanation:

`3 ln(a) - 6 ln(b) =>` use law of logs : `log(m^n) = n log(m):`

`= ln(a^3) - ln(b^6) =>` use: `log(m) - log(n) = log(m/n):`

`= ln[(a^3)/(b^6)]`