# How do you write 42 as a product of its prime factors?

Sep 22, 2016

$42 = 2 \times 3 \times 7$

#### Explanation:

The lowest $\textcolor{b l u e}{\text{prime number}}$ is 2. So we begin by dividing 42 by 2.

rArr42÷color(red)(2) =21

Now 21 cannot be divided by 2 so we now divide by the next highest $\textcolor{b l u e}{\text{prime number}}$ which is 3.

rArr21÷color(red)(3)=7

Now 7 is a $\textcolor{b l u e}{\text{prime number}}$

rArr7÷color(red)(7)=1 when we reach 1 we stop there.

Prime factors of 42 are $\textcolor{red}{2 , 3 \text{ and } 7}$

and as a product of prime factors, means expressing them in multiplication form.

$\Rightarrow 42 = 2 \times 3 \times 7 \leftarrow \text{ product of prime factors}$