How do you write $4 x^{2} + x 5 - 12 + 6 x$ $4x^2 + x 5- 12 + 6x$ in standard form?

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How do you write $4 x^{2} + x 5 - 12 + 6 x$ $4x^2 + x 5- 12 + 6x$ in standard form?

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Answer 1 · 2016-05-04T09:04:23

$4 x^{2} + 11 x - 12$ $4x^2+11x-12$

Explanation:

$Preamble about multiplication$ $color(blue)("Preamble about multiplication")$

$2 \times 5$ $2xx5$ gives the same answer as $5 \times 2$ $5xx2$

so $2 \times 5 = 5 \times 2$ $2xx5=5xx2$

so $x 5 = x \times 5 = 5 \times x = 5 x$ $x5=x xx5 = 5xx x = 5x$
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Write as $4 x^{2} + 5 x - 12 + 6 x$ $4x^2+5x-12+6x$

Regrouping $\to 4 x^{2} + 5 x + 6 x - 12$ $->4x^2+5x+6x-12$

$4 x^{2} + 11 x - 12$ $4x^2+11x-12$

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How do you write $4 x^{2} + x 5 - 12 + 6 x$ $4x^2 + x 5- 12 + 6x$ in standard form?

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How do you write 4x2+x5−12+6x4x^2 + x 5- 12 + 6x in standard form?

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How do you write $4 x^{2} + x 5 - 12 + 6 x$ $4x^2 + x 5- 12 + 6x$ in standard form?