How do you write $4x^2+x^5-12+6x$ in standard form?

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Answer 1 · 2016-11-11T04:16:10

$x^5+4x^2+6x-12$

Order the terms with exponents in descending order of power, and add the constant term (the one without a variable) at the end.

$4x^2+x^5-12+6x$

in standard form is

$x^5+4x^2+6x-12$ .

How do you write 4x^2+x^5-12+6x4x^2+x^5-12+6x in standard form?