# How do you write 4x^2+x^5-12+6x in standard form?

Nov 11, 2016

${x}^{5} + 4 {x}^{2} + 6 x - 12$

#### Explanation:

Order the terms with exponents in descending order of power, and add the constant term (the one without a variable) at the end.

$4 {x}^{2} + {x}^{5} - 12 + 6 x$

in standard form is

${x}^{5} + 4 {x}^{2} + 6 x - 12$.