How do you write $4 y = \frac{3}{16} x - 0.8$ $4y = 3/16x - 0.8$ in standard form?

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How do you write $4 y = \frac{3}{16} x - 0.8$ $4y = 3/16x - 0.8$ in standard form?

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Answer 1 · 2015-05-18T00:08:02

Problem: Write $4 y = \frac{3}{16} x - 0.8$ $4y=3/16x-0.8$ in standard form.

Since you have two different variables, I'm going to answer this question as if you want to know how to write the given equation as a linear equation in standard form, Ax+By=C.

Subtract $\frac{3}{16} x$ $3/16x$ from both sides of the equation.

$- \frac{3}{16} x + 4 y = - 0.8$ $-3/16x+4y=-0.8$

Multiply times $- 1$ $-1$ .

$\frac{3}{16} x - 4 y = 0.8$ $3/16x-4y=0.8$

Multiply both sides by $16$ $16$ .

$3 x - 64 y = 12.8$ $3x-64y=12.8$

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How do you write $4 y = \frac{3}{16} x - 0.8$ $4y = 3/16x - 0.8$ in standard form?

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