# How do you write 4y = 3/16x - 0.8 in standard form?

May 23, 2015

Standard form of a linear equation is (normally taken to be):
$A x + B y = C$ (sometimes with the restriction that $A > 0 \text{ & } A \epsilon \mathbb{Z}$)

Given $4 y = \frac{3}{16} x - 0.8$

Subtracting $\frac{3}{16} x$ from both sides
$- \frac{3}{16} x + 4 y = - 0.8$

Multiplying both sides by $\left(- 16\right)$ (see "sometimes" restriction above)

$3 x - 64 y = 12.8$
(which is in the requested "standard form")