# How do you write 4y^3-4y^2+3-y in standard form?

$4 {y}^{3} - 4 {y}^{2} - y + 3$
$4 {y}^{3} - 4 {y}^{2} + 3 - y$
$4 {y}^{3} - 4 {y}^{2} - y + 3$