# How do you write 5th degree taylor polynomial for sin(x)?

##### 1 Answer

Dec 8, 2016

With both x and a in radian measure,

#### Explanation:

Taylor expansion is about a neighboring point x = a, in contrast to

Maclaurin's that is about x = 0.

The expansion is

f(x) f(a) +(x-a)f'(a)+(x-a)^2/(2!)f''(a)+(x-a)^3/(3!)f'''(a)+.... Accordingly, here